Jugami Physics

High School · Physics · Unit 17

Electric Potential and Capacitors

What a volt really measures, how capacitors store charge and energy, and how fast they fill and empty.

A camera flash charges for a few seconds, then dumps its energy in about a thousandth of a second. A defibrillator does the same to restart a heart, and your phone's touchscreen notices your finger without you pressing anything. All three rely on capacitors, devices that store electric charge on two plates kept apart.

On this page you'll learn what electric potential and voltage mean, how equipotential lines work, and how the field between two plates depends on voltage and gap. Then you'll study capacitance, dielectrics, stored energy, capacitors in series and parallel, and how capacitors charge and discharge through a resistor. After that you can try the capacitor and RC calculator, read how the ideas developed and take the quiz. Current, resistance and Ohm's law are covered in Unit 5: Electricity and Circuits.

A parallel-plate capacitor connected to a battery, with straight, evenly spaced electric field lines running from the positive plate to the negative plate.

On this page

Key words first

Electric potential

The energy each coulomb of charge would have at a point, measured in volts (V).

Voltage

The difference in potential between two points: the work done per coulomb moving charge between them.

Equipotential

A line or surface where every point is at the same potential.

Capacitor

Two conductors separated by an insulator, used to store charge and energy.

Capacitance (C)

Charge stored per volt, measured in farads (F). Most real capacitors are microfarads (μF) or smaller.

Dielectric

An insulating material placed between the plates that increases capacitance.

Time constant (τ)

τ = RC, the time scale for a capacitor to charge or discharge through a resistor.

Farad

One coulomb per volt. A 1 F capacitor is huge; a typical flash capacitor is a few hundred μF.

Idea 1: Electric potential and voltage

Lifting a book gives it gravitational potential energy. In the same way, pushing a positive charge toward another positive charge takes work and gives it electric potential energy. Electric potential is that energy per coulomb, and the voltage between two points is the work needed per coulomb to move charge from one to the other:

V = W ÷ q

So 1 volt means 1 joule per coulomb. A 9 V battery gives each coulomb that passes through it 9 J of energy.

Around a point charge, the potential is the same at every point the same distance away, so the equipotentials are circles (spheres in 3D). Moving a charge along an equipotential takes no work. Field lines always cross equipotentials at right angles, pointing from high potential to low.

A positive point charge. Field lines point straight outward, and dashed equipotential circles at 30 V, 20 V and 10 V cross them at right angles. The circles are at distances in the ratio 1 : 1.5 : 3, because the potential falls off as 1 over the distance.30 V20 V10 Vequipotential(dashed)field line(arrow)
Around a positive charge, the potential falls with distance. Equipotential circles cross the field lines at right angles.

Idea 2: The field between two plates

Connect two flat, parallel metal plates to a battery and one becomes positive, the other negative. Between them, away from the edges, the electric field is uniform: the same strength and direction everywhere. Its strength is

E = V ÷ d

where d is the gap. That's why field strength can be written in volts per meter, which is the same unit as newtons per coulomb. The equipotentials between the plates are flat and evenly spaced. Halve the gap and the field doubles.

Two parallel plates at +12 V and 0 V, 4.0 mm apart. The field lines are straight and evenly spaced, and dashed equipotential lines at 9 V, 6 V and 3 V are evenly spaced between the plates. The field strength is 12 V divided by 0.0040 m, which is 3 000 V/m.9 V6 V3 V+12 V0 Vd = 4.0 mmE = V/d = 12 V ÷ 0.0040 m = 3 000 V/m
Between parallel plates the field is uniform, and the potential drops evenly from one plate to the other.

Idea 3: Capacitors and capacitance

A pair of plates like this is a capacitor. When it's connected to a battery, electrons are pulled off one plate and pushed onto the other, until the voltage across the plates matches the battery. One plate ends up with charge +Q and the other −Q. The charge stored is proportional to the voltage, and the ratio is the capacitance:

C = Q ÷ V

For a parallel-plate capacitor with plate area A and gap d,

C = ε₀A ÷ d, with ε₀ = 8.85 × 10⁻¹² F/m

Bigger plates and a smaller gap store more charge per volt. Filling the gap with an insulating dielectric, such as plastic or ceramic, multiplies the capacitance by the material's dielectric constant κ. The molecules in the dielectric line up slightly in the field, weakening it, so more charge fits for the same voltage.

A parallel-plate capacitor. Two metal plates, each of area A, are a gap d apart. One holds charge +Q and the other −Q, with five plus signs and five minus signs drawn. A dielectric slab fills part of the gap.+Q−Qgap ddielectricplatearea A
A parallel-plate capacitor: two plates of area A, a gap d and, often, a dielectric between them.

Idea 4: Energy stored in a capacitor

Charging a capacitor takes work, because each new bit of charge is pushed against the charge already there. The voltage rises steadily from 0 as charge builds up, so the average voltage is half the final one. The stored energy is the area under the charge–voltage graph:

U = ½QV = ½CV²

Doubling the voltage stores four times the energy. That's how a camera flash works: a battery slowly charges a capacitor to a few hundred volts, and the flash tube then releases that energy in a fraction of a millisecond. A defibrillator stores up to about 200–360 J and delivers it across a patient's chest in a few milliseconds.

Charge against voltage for a 10 μF capacitor charged to 12 V. The line rises to 120 μC. The shaded triangle under it is the stored energy: half of 120 μC times 12 V, which is 720 μJ.0481204080120voltage V (V)charge Q (μC)C = 10 μFarea = ½QV= 720 μJ
The stored energy is the triangle under the charge–voltage line: ½QV.

Idea 5: Capacitors in series and parallel

Capacitors combine the opposite way to resistors.

  • In parallel, each capacitor gets the full voltage and the charges add, so C = C₁ + C₂ + …. It's like making the plates bigger.
  • In series, each capacitor holds the same charge and the voltages add, so 1/C = 1/C₁ + 1/C₂ + …. It's like making the gap wider, and the total is less than the smallest one.
Two 2 μF capacitors. In series, 1 over C equals 1 over C₁ plus 1 over C₂, so the total is 1 μF. In parallel, the capacitances add, so the total is 4 μF.series2 μF2 μF1/C = 1/C₁ + 1/C₂C = 1 μFparallel2 μF2 μFC = C₁ + C₂C = 4 μF
Two 2 μF capacitors give 1 μF in series and 4 μF in parallel.

Idea 6: Charging and discharging: RC circuits

A capacitor charged through a resistor doesn't fill instantly. At first current flows easily, but as the capacitor's voltage rises it pushes back, so the current shrinks and charging slows down. The time scale is the time constant:

τ = RC

with R in ohms and C in farads giving seconds. After one time constant, a charging capacitor reaches about 63% of the supply voltage; a discharging one falls to about 37% of where it started. After 5τ it's within 1% of the end, and we treat it as full or empty. When discharging, V = V₀e−t/RC.

Time constants are everywhere: they set how long a flash takes to recharge, keep blinking lights and timers ticking, and smooth bumpy voltages in power supplies. A touchscreen works because your finger, a conductor, changes the capacitance at the spot you touch, and the phone senses the tiny change in how fast that spot charges.

Voltage on a capacitor while charging and discharging through a resistor. After one time constant, τ = RC, a charging capacitor reaches 63% of the supply voltage and a discharging one falls to 37% of its starting voltage. After 5τ both are within 1% of the end.63%37%0τ2τ3τ4τ5τ050%100%chargingdischargingtime (τ = RC)voltage on the capacitor
Charging and discharging both happen quickly at first and then slow down. Each time constant closes 63% of the remaining gap.

Worked examples

Try each one first, then open the solution. Use ε₀ = 8.85 × 10⁻¹² F/m.

1. Energy from a battery

A 9.0 V battery moves 2.0 C of charge. How much work does it do?

Show solution
W = qV = 2.0 × 9.0
= 18 J

Each coulomb gets 9 J, so 2 C gets 18 J.

2. Field between plates

Two plates 4.0 mm apart are connected to 12 V. Find the field between them.

Show solution
E = V ÷ d = 12 ÷ 0.0040
= 3 000 V/m

Remember to change millimeters to meters first.

3. Charge on a capacitor

A 10 μF capacitor is connected to 12 V. How much charge does it store?

Show solution
Q = CV = 10 × 10⁻⁶ × 12
= 1.2 × 10⁻⁴ C = 120 μC

Each plate holds 120 μC, one positive and one negative.

4. A parallel-plate capacitor

Two plates of area 0.010 m² are 1.0 mm apart with air between them. Find the capacitance.

Show solution
C = ε₀A ÷ d = 8.85 × 10⁻¹² × 0.010 ÷ 0.0010
= 8.85 × 10⁻¹¹ F ≈ 88.5 pF

Plates the size of a 10 cm square hold very little. Real capacitors roll up long, thin layers with a dielectric.

5. Energy in a camera flash

A 150 μF flash capacitor is charged to 300 V. How much energy does it store?

Show solution
U = ½CV² = 0.5 × 150 × 10⁻⁶ × 300²
= 6.75 J

Released in about 1 ms, that's a power of several kilowatts.

6. A time constant

A 100 μF capacitor discharges through a 10 kΩ resistor. Find the time constant and the time to be nearly empty.

Show solution
τ = RC = 10 000 × 100 × 10⁻⁶
= 1.0 s
Nearly empty after 5τ ≈ 5 s

After 1 s it's at 37% of its starting voltage.

Try it: capacitor and RC calculator

Q = CV, U = ½CV² and τ = RC calculator

How the ideas developed

The capacitor is older than the battery. Long before anyone could make a steady current, people were storing electric charge in glass jars, and sometimes getting a nasty shock from them.

  1. 1745 Ewald Georg von Kleist, and in 1746 Pieter van Musschenbroek in Leiden, store charge in a water-filled glass jar: the Leyden jar.
  2. 1752 Benjamin Franklin's experiments suggest lightning is electrical, and he studies how Leyden jars hold charge on their two surfaces.
  3. 1800 Alessandro Volta builds the first battery. The unit of potential, the volt, is later named after him.
  4. 1837 Michael Faraday shows that the material between the plates changes how much charge is stored, measuring what we now call the dielectric constant. The farad is named after him.
  5. 1909 Robert Millikan's oil-drop experiment uses the uniform field between charged plates to measure the charge of one electron.
  6. 1947 The first cardiac defibrillation of a human heart during surgery is performed in Cleveland.
  7. 2007 Multi-touch capacitive screens reach the mass market in smartphones.

Test yourself

The Electric Potential and Capacitors Check

Talk about it

  1. Why can a bird sit safely on a high-voltage power line?
  2. Why does a camera flash need a capacitor instead of running the flash straight from the battery?
  3. Why don't touchscreens respond to a gloved finger or a plastic pen?
  4. Large capacitors in old electronics can stay charged after unplugging. Why is that a safety concern?

Sources

  1. OpenStax, College Physics 2e, Chapter 19 "Electric Potential and Electric Field," Section 19.5 "Capacitors and Dielectrics" and Section 21.6 "DC Circuits Containing Resistors and Capacitors".
  2. Wikipedia, "Capacitor," "Leyden jar," "Defibrillation" and "Capacitive sensing."

Credits: all diagrams on this page, including the field and equipotential drawings, the charging curves and the share image, are original SVG made for Jugami.