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Linear Inequalities

Symbols, number-line graphs and step-by-step solving for grades 9–10.

A phone plan costs $20 a month plus 10 cents a text, and you can spend at most $35. How many texts can you send? The answer isn’t one number. Any number of texts from 0 up to 150 works. An inequality is how algebra describes a whole range of answers like that.

This page shows you how to read, graph and solve inequalities. Most of it works just like solving equations, with one important new rule. Every idea has a worked example, problems with answers you can reveal, and a practice machine at the end.

The inequality 2x + 1 ≥ 5 becomes x ≥ 2 after subtracting 1 and dividing by 2. Below, a number line from −4 to 8 has a closed circle at 2 and is shaded to the right, with an arrow.2x + 1 ≥ 5x ≥ 2subtract 1, then divide by 2−4−3−2−10123456782 is includedevery number from 2 upward is a solution

What is an inequality?

An equation says two things are equal. An inequality compares two things that might not be equal: one side is smaller or bigger than the other. There are four inequality symbols.

The four inequality symbols and how to read them
SymbolRead it asExampleIn words
<is less thanx < 4x is less than 4
>is greater thanx > −1x is greater than −1
≤is less than or equal tox ≤ 10x is at most 10
≥is greater than or equal tox ≥ 16x is at least 16

To remember which is which: the open, wide side of < or > always faces the bigger number. In 3 < 8, the wide side faces 8.

The line under ≤ and ≥ is half of an equals sign. It means “or equal to,” so x ≤ 10 allows 10 itself, but x < 10 doesn’t.

Read from the variable’s side

3 < x and x > 3 say the same thing: x is bigger than 3. If you flip a whole inequality around, so the sides trade places, the symbol turns around too. It’s usually easiest to read and graph an inequality when x is on the left.

A linear inequality is like a linear equation, but with one of these four symbols instead of =. The variable only appears to the first power: 3x − 5 ≥ 7 is linear, but x² < 9 is not.

Solutions are sets

A solution of an inequality is a number that makes it true. Most linear equations have exactly one solution. Most inequalities have infinitely many.

Take x > 3. The numbers 4, 10, 3.5, 3.01 and a million are all solutions. 3 is not, because 3 is not greater than itself. The collection of every solution is called the solution set.

Here’s how to test some numbers in 2x − 1 < 5: put each one in for x and see whether the statement comes out true.

Testing four numbers in 2x − 1 < 5
xPut it inSolution?
−22(−2) − 1 = −5, and −5 < 5Yes
02(0) − 1 = −1, and −1 < 5Yes
32(3) − 1 = 5, and 5 < 5No: 5 is not less than 5
52(5) − 1 = 9, and 9 < 5No

Solving gives the whole set at once: 2x − 1 < 5 becomes x < 3. That matches the table. −2 and 0 are below 3, while 3 and 5 are not.

Later courses sometimes write a solution set in set-builder notation: {x | x < 3} is read “the set of all x such that x is less than 3.” On this page we’ll mostly use plain inequalities, number-line graphs and interval notation.

Graphing on a number line

You can’t list infinitely many solutions, but you can draw them. A number-line graph uses two marks:

  • A circle at the boundary number. It’s open (hollow) for < and >, because the boundary is not a solution. It’s closed (filled in) for ≤ and ≥, because the boundary is a solution.
  • Shading over every solution. x > 3 and x ≥ 3 shade to the right, toward bigger numbers. x < 3 and x ≤ 3 shade to the left. The arrow means “and so on, forever.”

x < 3

Number line graph of x < 3. Open circle at 3, shaded to the left.−3−2−1012345678

Open circle: 3 is not included.

x ≤ 3

Number line graph of x ≤ 3. Closed circle at 3, shaded to the left.−3−2−1012345678

Closed circle: 3 is included.

x > −1

Number line graph of x > −1. Open circle at −1, shaded to the right.−6−5−4−3−2−1012345

Open circle, shaded right.

x ≥ −1

Number line graph of x ≥ −1. Closed circle at −1, shaded to the right.−6−5−4−3−2−1012345

Closed circle, shaded right.

Same boundary, different circles. Open means “not this number”; closed means “this number too.”

Quick shading check

When x is on the left, the symbol points the way to shade: x < 3 points left, x > 3 points right. If x is on the right, as in 5 ≥ x, rewrite it first as x ≤ 5. To be sure, pick any number in the shaded part and test it.

Try it yourself. Choose a type of inequality, a symbol and a number, and the grapher draws it. Then test numbers to see which ones are solutions. You can also tap the number line to place the test point.

One-step inequalities

You solve an inequality with the same moves as an equation: add, subtract, multiply or divide both sides by the same number. The goal is still to get x alone. Adding or subtracting never changes the direction of the sign, and neither does multiplying or dividing by a positive number.

Example 1: subtract

x + 7 > 3Startx > −4Subtract 7 from both sides. The sign stays >
Number line graph of x > −4. Open circle at −4, shaded to the right.x > −4−9−8−7−6−5−4−3−2−101

Example 2: add

x − 5 ≤ 2Startx ≤ 7Add 5 to both sides
Number line graph of x ≤ 7. Closed circle at 7, shaded to the left.x ≤ 723456789101112

Example 3: divide

4x ≥ −20Startx ≥ −5Divide both sides by 4. 4 is positive, so the sign stays ≥, even though −20 is negative
Number line graph of x ≥ −5. Closed circle at −5, shaded to the right.x ≥ −5−10−9−8−7−6−5−4−3−2−10

Example 4: multiply

x/3 < 2Startx < 6Multiply both sides by 3. Positive, so the sign stays <
Number line graph of x < 6. Open circle at 6, shaded to the left.x < 61234567891011

Your turn

Solve x + 9 ≤ 4
x ≤ −5Subtract 9 from both sides
Number line graph of x ≤ −5. Closed circle at −5, shaded to the left.x ≤ −5−10−9−8−7−6−5−4−3−2−10
Solve 5x > −15
x > −3Divide both sides by 5 (positive, so no flip)
Number line graph of x > −3. Open circle at −3, shaded to the right.x > −3−8−7−6−5−4−3−2−1012
Solve x/2 ≥ −3
x ≥ −6Multiply both sides by 2
Number line graph of x ≥ −6. Closed circle at −6, shaded to the right.x ≥ −6−11−10−9−8−7−6−5−4−3−2−1

The flip rule: multiplying or dividing by a negative

Here is the one place where inequalities behave differently from equations. Start with a true statement, 2 < 5, and do the same thing to both sides. Watch what happens to the sign.

Doing the same thing to both sides of 2 < 5
Do this to both sidesTrue statementSign
Start2 < 5<
Add 35 < 8stays <
Subtract 10−8 < −5stays <
Multiply by 24 < 10stays <
Divide by 21 < 2.5stays <
Multiply by −1−2 > −5flips to >
Multiply by −3−6 > −15flips to >
Divide by −2−1 > −2.5flips to >

Multiplying by −1 turns 2 into −2 and 5 into −5. But −2 is greater than −5: on a number line, −2 is to the right. If you kept the old sign, you’d get −2 < −5, which is false.

A number line from −6 to 6. Teal dots at 2 and 5, labeled 2 is less than 5. Curved arrows carry each dot to its mirror image across zero: 2 goes to −2 and 5 goes to −5, shown as coral dots labeled −2 is greater than −5. The bigger number ends up on the left, so the order reverses.−6−5−4−3−2−101234562 < 5−2 > −5multiply by −1: every number jumps to its mirror image across 0
Multiplying by a negative mirrors every number across 0. The number that was farther right ends up farther left, so the order reverses.

Multiply or divide by a negative → flip the sign.

So < becomes >, > becomes <, ≤ becomes ≥, and ≥ becomes ≤.

Example 1

−3x < 12Startx > −4Divide both sides by −3 and flip < to >
Number line graph of x > −4. Open circle at −4, shaded to the right.x > −4−9−8−7−6−5−4−3−2−101

Example 2

−x/2 ≥ 3Startx ≤ −6Multiply both sides by −2 and flip ≥ to ≤
Number line graph of x ≤ −6. Closed circle at −6, shaded to the left.x ≤ −6−11−10−9−8−7−6−5−4−3−2−1

Example 3

5 − x > 1Start−x > −4Subtract 5 from both sides. No flip yetx < 4Multiply both sides by −1 and flip > to <
Number line graph of x < 4. Open circle at 4, shaded to the left.x < 4−10123456789

Check Example 1

Pick a number in x > −4, like 0: −3(0) = 0, and 0 < 12 is true. Pick one outside, like −5: −3(−5) = 15, and 15 < 12 is false. The flipped answer passes both tests.

When NOT to flip

  • Adding or subtracting, even a negative number: x − 4 > −6 becomes x > −2.
  • Multiplying or dividing by a positive number, even when the other side is negative: 2x < −8 becomes x < −4.

Only the sign of the number you multiply or divide by matters, not the signs of the numbers already in the inequality.

Your turn

Solve −4x ≥ 28
x ≤ −7Divide both sides by −4 and flip ≥ to ≤
Number line graph of x ≤ −7. Closed circle at −7, shaded to the left.x ≤ −7−12−11−10−9−8−7−6−5−4−3−2
Solve −x/3 < 2
x > −6Multiply both sides by −3 and flip < to >
Number line graph of x > −6. Open circle at −6, shaded to the right.x > −6−11−10−9−8−7−6−5−4−3−2−1
Solve 2 − x ≤ 7
−x ≤ 5Subtract 2 from both sidesx ≥ −5Multiply both sides by −1 and flip ≤ to ≥
Number line graph of x ≥ −5. Closed circle at −5, shaded to the right.x ≥ −5−10−9−8−7−6−5−4−3−2−10

Multi-step inequalities

Use the same order as with equations: distribute and combine like terms first, undo adding or subtracting next, then multiply or divide. Only flip at the step where you multiply or divide by a negative.

Example 1

3x − 4 ≤ 11Start3x ≤ 15Add 4 to both sidesx ≤ 5Divide both sides by 3
Number line graph of x ≤ 5. Closed circle at 5, shaded to the left.x ≤ 5012345678910

Example 2

7 − 2x > 13Start−2x > 6Subtract 7 from both sidesx < −3Divide both sides by −2 and flip > to <
Number line graph of x < −3. Open circle at −3, shaded to the left.x < −3−8−7−6−5−4−3−2−1012

Example 3: distribute

2(x + 3) ≥ 4Start2x + 6 ≥ 4Distribute the 22x ≥ −2Subtract 6 from both sidesx ≥ −1Divide both sides by 2
Number line graph of x ≥ −1. Closed circle at −1, shaded to the right.x ≥ −1−6−5−4−3−2−101234

Example 4: distribute a negative

−3(x − 2) < 15Start−3x + 6 < 15Distribute −3: −3 · x and −3 · (−2)−3x < 9Subtract 6 from both sidesx > −3Divide both sides by −3 and flip < to >
Number line graph of x > −3. Open circle at −3, shaded to the right.x > −3−8−7−6−5−4−3−2−1012

Your turn

Solve 5x + 2 > −13
5x > −15Subtract 2 from both sidesx > −3Divide both sides by 5
Number line graph of x > −3. Open circle at −3, shaded to the right.x > −3−8−7−6−5−4−3−2−1012
Solve x/4 − 1 ≤ 2
x/4 ≤ 3Add 1 to both sidesx ≤ 12Multiply both sides by 4
Number line graph of x ≤ 12. Closed circle at 12, shaded to the left.x ≤ 127891011121314151617
Solve 4 − 3(x + 1) ≥ 10
4 − 3x − 3 ≥ 10Distribute −31 − 3x ≥ 10Combine 4 − 3−3x ≥ 9Subtract 1 from both sidesx ≤ −3Divide both sides by −3 and flip ≥ to ≤
Number line graph of x ≤ −3. Closed circle at −3, shaded to the left.x ≤ −3−8−7−6−5−4−3−2−1012

Variables on both sides

Collect the x-terms on one side and the numbers on the other. Here’s a handy trick: move the smaller x-term. Then the x-term that’s left has a positive coefficient, and you won’t need to flip at all.

Example 1

5x − 2 > 2x + 10Start3x − 2 > 10Subtract 2x from both sides3x > 12Add 2 to both sidesx > 4Divide both sides by 3
Number line graph of x > 4. Open circle at 4, shaded to the right.x > 4−10123456789

Example 2: x ends up on the right

2x + 9 ≤ 6x − 3Start9 ≤ 4x − 3Subtract 2x (the smaller x-term) from both sides12 ≤ 4xAdd 3 to both sides3 ≤ xDivide both sides by 4x ≥ 3Read it from x’s side: 3 ≤ x means x ≥ 3
Number line graph of x ≥ 3. Closed circle at 3, shaded to the right.x ≥ 3−2−1012345678

You could also do Example 2 by subtracting 6x instead. You’d get −4x + 9 ≤ −3, then −4x ≤ −12, and dividing by −4 (with a flip) gives the same answer, x ≥ 3. Both ways are correct. The trick just saves you a flip.

Your turn

Solve 7x + 1 < 4x − 8
3x + 1 < −8Subtract 4x from both sides3x < −9Subtract 1 from both sidesx < −3Divide both sides by 3
Number line graph of x < −3. Open circle at −3, shaded to the left.x < −3−8−7−6−5−4−3−2−1012
Solve x − 4 ≥ 3x + 6
−4 ≥ 2x + 6Subtract x (the smaller x-term) from both sides−10 ≥ 2xSubtract 6 from both sides−5 ≥ xDivide both sides by 2x ≤ −5Read it from x’s side
Number line graph of x ≤ −5. Closed circle at −5, shaded to the left.x ≤ −5−10−9−8−7−6−5−4−3−2−10

Always true or never true

Sometimes the x-terms cancel and you’re left with a statement with no x at all. Then the answer depends only on whether that statement is true.

Always true

2(x + 3) > 2x + 1Start2x + 6 > 2x + 1Distribute6 > 1Subtract 2x from both sides. True, whatever x isAll real numbersEvery number is a solution
Number line graph of All real numbers. The whole line is shaded, with arrows at both ends: every number works.All real numbers−5−4−3−2−1012345

Never true

3x − 4 ≥ 3(x + 1)Start3x − 4 ≥ 3x + 3Distribute−4 ≥ 3Subtract 3x from both sides. False, whatever x isNo solutionNo number makes it true
Number line graph of No solution. Nothing is shaded: no solution.No solution−5−4−3−2−1012345

The graph of “all real numbers” is the whole line, shaded, with arrows at both ends. For “no solution” nothing is shaded.

Watch the “or equal to”

4x + 1 > 4x + 1 simplifies to 1 > 1, which is false: no solution. But 4x + 1 ≥ 4x + 1 simplifies to 1 ≥ 1, which is true: all real numbers. One small line under the sign changes the whole answer.

Compound inequalities: and, or

A compound inequality joins two inequalities with and or or.

  • And means both must be true. “x is greater than −2 and at most 3” describes the numbers between −2 and 3. We write it in one chain: −2 < x ≤ 3. Read it as “x is between −2 and 3, including 3.”
  • Or means at least one must be true. x < −1 or x ≥ 4 describes numbers outside the stretch from −1 to 4.

−2 < x ≤ 3

Number line graph of −2 < x ≤ 3. Open circle at −2 and closed circle at 3, shaded between them.−6−5−4−3−2−10123456

And: the part between, where both are true.

x < −1 or x ≥ 4

Number line graph of x < −1 or x ≥ 4. Open circle at −1, shaded to the left. Also: Closed circle at 4, shaded to the right.−5−4−3−2−1012345678

Or: two separate pieces.

An “and” graph is usually one piece. An “or” graph is usually two pieces pointing away from each other.

To solve a chain like −3 < 2x + 1 ≤ 7, do the same thing to all three parts at once, so that x is alone in the middle. If you divide by a negative, flip both signs.

Example 1: and

−3 < 2x + 1 ≤ 7Start−4 < 2x ≤ 6Subtract 1 from all three parts−2 < x ≤ 3Divide all three parts by 2
Number line graph of −2 < x ≤ 3. Open circle at −2 and closed circle at 3, shaded between them.−2 < x ≤ 3−5−4−3−2−10123456

Example 2: and, with a negative

−5 ≤ 1 − 2x < 7Start−6 ≤ −2x < 6Subtract 1 from all three parts3 ≥ x > −3Divide all three parts by −2 and flip both signs−3 < x ≤ 3Rewrite it with the smaller number on the left
Number line graph of −3 < x ≤ 3. Open circle at −3 and closed circle at 3, shaded between them.−3 < x ≤ 3−6−5−4−3−2−10123456

Example 3: or

x + 2 < −1 or 3x > 9Start: solve each part on its ownx < −3 or 3x > 9Left part: subtract 2x < −3 or x > 3Right part: divide by 3
Number line graph of x < −3 or x > 3. Open circle at −3, shaded to the left. Also: Open circle at 3, shaded to the right.x < −3 or x > 3−6−5−4−3−2−10123456

Order matters

Always write a chain from smaller to larger, like a number line: −3 < x ≤ 3, not 3 ≥ x > −3 (correct, but hard to read).

Never squash an “or” into a chain. 3 < x < −3 would mean x is bigger than 3 and smaller than −3 at the same time. No number does that.

Two surprises

An “and” can have no solution: x < 1 and x > 4 has no overlap. An “or” can cover everything: x < 5 or x > 1 includes every real number, because each number is less than 5, greater than 1, or both.

Your turn

Solve 1 ≤ x + 4 < 6
−3 ≤ x < 2Subtract 4 from all three parts
Number line graph of −3 ≤ x < 2. Closed circle at −3 and open circle at 2, shaded between them.−3 ≤ x < 2−6−5−4−3−2−1012345
Solve −6 < 3x − 3 ≤ 9
−3 < 3x ≤ 12Add 3 to all three parts−1 < x ≤ 4Divide all three parts by 3
Number line graph of −1 < x ≤ 4. Open circle at −1 and closed circle at 4, shaded between them.−1 < x ≤ 4−4−3−2−101234567
Solve 2x − 1 ≤ −5 or x − 3 > 1
2x ≤ −4 or x − 3 > 1Left part: add 1x ≤ −2 or x − 3 > 1Left part: divide by 2x ≤ −2 or x > 4Right part: add 3
Number line graph of x ≤ −2 or x > 4. Closed circle at −2, shaded to the left. Also: Open circle at 4, shaded to the right.x ≤ −2 or x > 4−5−4−3−2−101234567

Interval notation

Interval notation is a short way to write a solution set, used a lot in later courses. You write the left end and the right end of the shaded part, separated by a comma.

  • A parenthesis ( or ) means that end is not included, like an open circle.
  • A bracket [ or ] means that end is included, like a closed circle.
  • ∞ (infinity) and −∞ mean the shading goes on forever. They always get a parenthesis, because infinity isn’t a number you can reach.
  • Write the smaller end first. Use ∪ (“union”) to join the two pieces of an “or.”
Inequalities and their interval notation
InequalityInterval notationGraph
x > 3(3, ∞)open circle at 3, shaded right
x ≤ −1(−∞, −1]closed circle at −1, shaded left
−2 < x ≤ 5(−2, 5]open at −2, closed at 5, shaded between
x < −3 or x ≥ 3(−∞, −3) ∪ [3, ∞)two pieces pointing outward
all real numbers(−∞, ∞)the whole line
no solution∅ (the empty set)nothing shaded

Don’t mix it up with a point

(3, 5) in interval notation means every number between 3 and 5. In graphing, the same symbols name the point at x = 3, y = 5. Context tells you which one is meant.

Checking with test points

With an equation, you check one number. With an inequality, check three things:

  1. The boundary. Put the boundary number in. The two sides should come out equal.
  2. A test point inside the shaded part. It should make the original inequality true.
  3. A test point outside the shaded part. It should make the original inequality false.

Suppose you solved 4 − 3x ≤ 10 and got x ≥ −2. Here’s the check, always in the original inequality:

Checking x ≥ −2 as the answer to 4 − 3x ≤ 10
xPut it in 4 − 3x ≤ 10Result
−24 − 3(−2) = 10, and 10 ≤ 10True, and the sides are equal: −2 is the boundary, and ≤ includes it
04 − 3(0) = 4, and 4 ≤ 10True: inside the answer, as it should be
−54 − 3(−5) = 19, and 19 ≤ 10False: outside the answer, as it should be

Test points are great at catching a forgotten flip. If you had written x ≤ −2 instead, −5 would be inside your answer, but the table shows −5 doesn’t work. That tells you the sign points the wrong way.

Word problems: at least, at most

Word problems use phrases instead of symbols. These are the ones you’ll meet most:

Words and the inequality symbols they mean
WordsSymbolExample
at least, no less than, a minimum of≥You must be at least 16: a ≥ 16
at most, no more than, a maximum of, up to≤At most 30 students: s ≤ 30
more than, greater than, over, exceeds>More than 8 hours: h > 8
less than, fewer than, under, below<Fewer than 5 mistakes: m < 5

Careful: “5 less than a number” is the expression n − 5, not an inequality. It’s “is less than” that means <.

The steps are the same as for equation word problems: name the variable, write the inequality, solve it, then answer the question in a sentence. Make sure the answer makes sense, since you can’t buy half a ticket or send −3 texts.

Example 1: phone plan

$20 a month plus $0.10 per text. You can spend at most $35. Let t be the number of texts.

20 + 0.10t ≤ 35“At most” means ≤0.10t ≤ 15Subtract 20 from both sidest ≤ 150Divide both sides by 0.10

Answer: at most 150 texts. Since t counts texts, it’s a whole number from 0 to 150.

Example 2: test average

Your scores are 78, 85 and 90. What do you need on the fourth test to average at least 85? Let s be the score.

(78 + 85 + 90 + s)/4 ≥ 85Average of four tests, at least 85253 + s ≥ 340Multiply both sides by 4, and add 78 + 85 + 90s ≥ 87Subtract 253 from both sides

Answer: at least 87. Tests are scored out of 100, so the real answer is 87 ≤ s ≤ 100, a compound inequality.

Example 3: elevator

An elevator can carry up to 1200 pounds. A 180-pound worker loads boxes that weigh 60 pounds each. How many boxes can go up in one trip? Let b be the number of boxes.

180 + 60b ≤ 1200“Up to” means ≤60b ≤ 1020Subtract 180 from both sidesb ≤ 17Divide both sides by 60

Answer: at most 17 boxes.

Your turn

Sam has $50 and saves $15 a week. After how many weeks will he have more than $200?
50 + 15w > 200“More than” means >15w > 150Subtract 50 from both sidesw > 10Divide both sides by 15

After exactly 10 weeks he has $200, which isn’t more than $200. So the answer is 11 weeks.

A taxi charges $3 plus $2.50 per mile. You want to spend no more than $18. How far can you ride?
3 + 2.5m ≤ 18“No more than” means ≤2.5m ≤ 15Subtract 3 from both sidesm ≤ 6Divide both sides by 2.5

At most 6 miles.

Common mistakes

✗−2x > 6, so x > −3.✓Dividing by −2 flips the sign: x < −3. Test x = 0: −2(0) = 0, and 0 > 6 is false, so 0 can’t be a solution. But 0 is in x > −3.
✗3x < −12, so x > −4 “because of the negative.”✓Only multiplying or dividing by a negative flips. Here you divide by 3, which is positive: x < −4.
✗x − 4 > −6, so x < −2.✓Adding never flips: x > −2.
✗Graphing x ≤ 2 with an open circle.✓“Or equal to” includes 2, so use a closed (filled) circle. Open circles are for < and >.
✗Reading 5 > x as “x is greater than 5.”✓Read it from x’s side: x < 5, so x is less than 5.
✗Writing “x < −3 or x > 3” as 3 < x < −3.✓No number is both bigger than 3 and smaller than −3. Keep the two parts joined with “or.”
✗Getting 6 > 1 and writing x > 6.✓When x disappears and the statement is true, the answer is all real numbers. If it’s false, there’s no solution.
✗Solving −3 < x + 2 < 5 by subtracting 2 from the middle only: −3 < x < 5.✓Subtract 2 from all three parts: −5 < x < 3.

Practice problems

Solve each one, then open the answer to check your steps and the graph. Numbers 1–4 are one step, 5–9 are multi-step, 10–11 are special cases, 12–13 are compound, and 14 is a word problem.

  1. x − 8 ≥ −3
    Show answer
    x ≥ 5Add 8 to both sides
    Number line graph of x ≥ 5. Closed circle at 5, shaded to the right.x ≥ 5012345678910
  2. 7x < −35
    Show answer
    x < −5Divide both sides by 7 (positive: no flip)
    Number line graph of x < −5. Open circle at −5, shaded to the left.x < −5−10−9−8−7−6−5−4−3−2−10
  3. −5x ≤ 30
    Show answer
    x ≥ −6Divide both sides by −5 and flip ≤ to ≥
    Number line graph of x ≥ −6. Closed circle at −6, shaded to the right.x ≥ −6−11−10−9−8−7−6−5−4−3−2−1
  4. −x/4 > 1
    Show answer
    x < −4Multiply both sides by −4 and flip > to <
    Number line graph of x < −4. Open circle at −4, shaded to the left.x < −4−9−8−7−6−5−4−3−2−101
  5. 3x + 7 > −2
    Show answer
    3x > −9Subtract 7 from both sidesx > −3Divide both sides by 3
    Number line graph of x > −3. Open circle at −3, shaded to the right.x > −3−8−7−6−5−4−3−2−1012
  6. 10 − 4x ≥ 2
    Show answer
    −4x ≥ −8Subtract 10 from both sidesx ≤ 2Divide both sides by −4 and flip
    Number line graph of x ≤ 2. Closed circle at 2, shaded to the left.x ≤ 2−3−2−101234567
  7. 2(x − 5) < 3x − 4
    Show answer
    2x − 10 < 3x − 4Distribute−10 < x − 4Subtract 2x (the smaller x-term)−6 < xAdd 4 to both sidesx > −6Read it from x’s side
    Number line graph of x > −6. Open circle at −6, shaded to the right.x > −6−11−10−9−8−7−6−5−4−3−2−1
  8. 6x − 1 ≤ 2x + 11
    Show answer
    4x − 1 ≤ 11Subtract 2x from both sides4x ≤ 12Add 1 to both sidesx ≤ 3Divide both sides by 4
    Number line graph of x ≤ 3. Closed circle at 3, shaded to the left.x ≤ 3−2−1012345678
  9. x/2 + 3 > x/3 + 4
    Show answer
    3x + 18 > 2x + 24Multiply every term by 6 (positive: no flip)x + 18 > 24Subtract 2x from both sidesx > 6Subtract 18 from both sides
    Number line graph of x > 6. Open circle at 6, shaded to the right.x > 61234567891011
  10. 4(x + 2) ≤ 4x + 5
    Show answer
    4x + 8 ≤ 4x + 5Distribute8 ≤ 5Subtract 4x: falseNo solutionNo number works
    Number line graph of No solution. Nothing is shaded: no solution.No solution−5−4−3−2−1012345
  11. −2(x − 1) > −2x − 3
    Show answer
    −2x + 2 > −2x − 3Distribute −22 > −3Add 2x: trueAll real numbersEvery number works
    Number line graph of All real numbers. The whole line is shaded, with arrows at both ends: every number works.All real numbers−5−4−3−2−1012345
  12. −4 ≤ 3x + 2 < 11
    Show answer
    −6 ≤ 3x < 9Subtract 2 from all three parts−2 ≤ x < 3Divide all three parts by 3
    Number line graph of −2 ≤ x < 3. Closed circle at −2 and open circle at 3, shaded between them.−2 ≤ x < 3−5−4−3−2−10123456
  13. 5 − x < 2 or 2x + 4 ≤ −6
    Show answer
    −x < −3 or 2x ≤ −10Subtract 5 on the left, subtract 4 on the rightx > 3 or x ≤ −5Left: multiply by −1 and flip. Right: divide by 2x ≤ −5 or x > 3Write the left-most piece first
    Number line graph of x ≤ −5 or x > 3. Closed circle at −5, shaded to the left. Also: Open circle at 3, shaded to the right.x ≤ −5 or x > 3−8−7−6−5−4−3−2−10123456
  14. A club needs to raise at least $600. It has $150 and sells candles for $9 each. How many candles must it sell? Use c.
    Show answer
    150 + 9c ≥ 600“At least” means ≥9c ≥ 450Subtract 150 from both sidesc ≥ 50Divide both sides by 9
    Number line graph of c ≥ 50. Closed circle at 50, shaded to the right.c ≥ 504546474849505152535455

    At least 50 candles.

History: where do < and > come from?

The signs < and > first appeared in print in 1631, in an algebra book by the English mathematician Thomas Harriot (about 1560–1621). Its Latin title is Artis Analyticae Praxis, roughly “The Practice of the Analytic Art.” The book explains the new sign with the example a > b, meaning “a is greater than b.”

Harriot never saw it. He died in 1621, and the book was put together from his papers ten years later, mainly by his friend Walter Warner. Historians who have studied Harriot’s handwritten pages say he used different-looking signs himself. So the shapes we use today may have been chosen by the editors, not by Harriot.

Harriot did much more than algebra. He taught navigation to the sailors on Sir Walter Raleigh’s voyages, sailed to Roanoke Island in what’s now North Carolina in 1585, and on 26 July 1609 sketched the Moon through a telescope, the earliest telescope observation known in England.

And ≤ and ≥?

Those came later. The English mathematician John Wallis used a version with a single bar above the sign in 1670. The French scientist Pierre Bouguer used signs with two bars underneath, ≦ and ≧, in 1734. The single-bar ≤ and ≥ we use now became standard later still. The equals sign itself is older than all of them: Robert Recorde introduced it in 1557, as the Linear Equations history section explains.

How do we know?

The 1631 book survives and can be read today. Historians compare it with Harriot’s own manuscripts, thousands of pages of which are kept in the British Library and at Petworth House, England. They still disagree about how much of the printed book reflects Harriot’s own choices.

Practice: Solve It

A new inequality every time, with hints, full steps and a graph of the answer. Choose a level, or mix them all. Type your answer like x > 3, x ≤ −2, −1 < x ≤ 4 or x < 1 or x > 5. You can type <= and >=, or tap the symbol buttons. Interval notation like (−∞, 3] works too.

Sources

Credits: all illustrations and number-line graphs on this page are original SVG drawings made for Jugami. Every worked example and answer was checked by testing numbers in the original inequality and in every step.