Jugami Geometry

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Similarity

Similar figures have the same shape but not always the same size. One is a scaled copy of the other.

This unit covers dilations and scale factors, how to name similar triangles, the AA, SSS~ and SAS~ shortcuts, parallel lines that split sides in proportion, the altitude in a right triangle, how area and volume scale, and how to measure things you can’t reach.

A dilation on graph paper. Rays from a center point O pass through the corners of a small triangle ABC and on to a triangle A′B′C′ three times as far from O. Scale factor k = 3: every side is multiplied by 3 and the angles stay the sameOABCA′B′C′k = 3every side × 3

Dilations and the scale factor

A dilation enlarges or shrinks a figure from a fixed point called the center. Every point moves along the line from the center, and its distance from the center is multiplied by the same number k, the scale factor. In the picture at the top of the page, k = 3, so OA′ = 3 · OA.

  • If k > 1, the image is larger (an enlargement).
  • If 0 < k < 1, the image is smaller (a reduction).
  • If k = 1, nothing moves.

A dilation multiplies every length by k, keeps every angle the same, and sends each side to a parallel side (or to a side on the same line).

What similar means, and naming order

Triangle ABC with sides AB 7, BC 6 and CA 5, and a larger triangle DEF with sides DE 10.5, EF 9 and FD 7.5. Matching arcs show angle A equals angle D, B equals E and C equals F. Each side of DEF is 1.5 times the matching side of ABCABC765DEF10.597.5
△ABC ~ △DEF with scale factor 1.5. Matching arcs mark equal angles.

Two figures are similar if a dilation followed by rigid motions (slides, turns and flips) moves one exactly onto the other. For two triangles that means:

  • all three pairs of matching angles are equal, and
  • all three pairs of matching sides are in the same ratio, the scale factor.

We write △ABC ~ △DEF, read “triangle ABC is similar to triangle DEF.” As with congruence, the order of the letters tells you which parts match: A ↔ D, B ↔ E, C ↔ F. In the figure, DE/AB = EF/BC = FD/CA = 10.5/7 = 9/6 = 7.5/5 = 1.5.

Congruent triangles are the special case where the scale factor is 1.

Explorer: dilate a triangle

Drag the center O (or tab to it and use the arrow keys; hold Shift for bigger steps) and move the slider to change the scale factor k. The table shows the side, perimeter and area ratios. Each grid square is 1 unit.

Interactive figure: a blue triangle ABC, a center point O, dashed rays from O through each corner, and the orange image triangle A′B′C′ for the chosen scale factor

Shortcuts: AA, SSS~ and SAS~

Three pairs of similar triangles, each small triangle beside one 1.5 times larger. AA: two pairs of equal angles marked. SSS similarity: sides 6, 5, 4 and 9, 7.5, 6, all in ratio 1.5. SAS similarity: sides 6 and 4 with the angle between them, matched by sides 9 and 6 with the same angleAA645967.5SSS~6496SAS~
Each pair is similar with scale factor 1.5. The marks show what each shortcut needs.
NameWhat you need to know
AATwo pairs of equal angles. The third pair is then equal too, because the angles of a triangle add to 180°.
SSS~All three pairs of sides in the same ratio.
SAS~Two pairs of sides in the same ratio, and the angles between them equal.

To compare sides, pair shortest with shortest, middle with middle and longest with longest, then divide. For SSS~, the three ratios must all be equal. Notice that AA needs no lengths at all. That is why it was useless for congruence but is the most common way to prove similarity.

The side-splitter theorem and the midsegment

Left: triangle ABC with segment DE parallel to BC. AD is 4, DB is 6, AE is 6 and EC is 9, so AD to DB equals AE to EC. Right: triangle PQR with M and N the midpoints of PQ and PR; the midsegment MN is parallel to QR and half as longABCDE4669PQRMNMN = ½ QRDE ∥ BC
Left: 4 : 6 = 6 : 9. Right: M and N are midpoints, so MN is half of QR.

Side-splitter theorem: if a line parallel to one side of a triangle crosses the other two sides, it cuts them in the same ratio. In the figure, DE ∥ BC, so AD : DB = AE : EC, and indeed 4 : 6 = 6 : 9. The converse is also true: if a segment cuts two sides in the same ratio, it is parallel to the third side.

Why it works: the parallel line makes equal corresponding angles, so △ADE ~ △ABC by AA.

Midsegment theorem: the segment joining the midpoints of two sides is parallel to the third side and half as long. This is the side splitter with ratio 1 : 1, where the small triangle is a copy of the big one with scale factor ½.

The altitude to the hypotenuse

Right triangle ABC with the right angle at C. The altitude CD meets the hypotenuse AB at D, splitting it into AD 4 and DB 9. The altitude CD is 6, because 6 squared is 4 times 9ABCDAD = 4DB = 9CD = 6
The altitude CD splits the right triangle into two smaller triangles, both similar to the whole.

Draw the altitude from the right angle C to the hypotenuse AB. It cuts △ABC into two smaller right triangles, and all three triangles are similar: △ACB ~ △ADC ~ △CDB. Each small triangle shares an acute angle with the big one, so AA applies.

Matching sides of △ADC and △CDB give AD/CD = CD/DB, so CD² = AD · DB. The altitude is the geometric mean of the two pieces of the hypotenuse. In the figure, CD² = 4 · 9 = 36, so CD = 6.

Perimeter, area and volume

Three squares on graph paper with sides 1, 2 and 3. The side 2 square holds 4 unit squares and the side 3 square holds 9: when lengths are multiplied by k, area is multiplied by k squaredside 1, area 1side 2, area 4side 3, area 9
Double the side, four times the area. Triple the side, nine times the area.

If two figures are similar with scale factor k:

  • every length, including the perimeter, is multiplied by k;
  • every area is multiplied by k²;
  • for similar solids, every volume is multiplied by k³.

So a model built at scale 1 : 10 has 1/100 of the real surface area and 1/1000 of the real volume. To go backwards, take a square root of an area ratio, or a cube root of a volume ratio, to find k.

Real-world uses: shadows, maps and models

A tree and a 2 metre stick stand on flat ground in sunlight. The stick casts a 3 metre shadow and the tree casts a 15 metre shadow. The parallel sun rays make two similar right triangles, so the tree is 10 metres tallh = ?shadow 15 m2 m3 msun’s rays are parallel
Height ÷ shadow is the same for the stick and the tree: 2 ÷ 3 = 10 ÷ 15.

Shadows. At any moment, the sun’s rays reach the ground at the same angle everywhere nearby. An upright object, its shadow and the ray over its top form a right triangle, so all of these triangles are similar by AA. Measure a stick and its shadow, measure the shadow of something tall, and one proportion gives the height.

There is an old story about this. Thales of Miletus is said to have measured the height of the Egyptian pyramids from their shadows. The accounts were written centuries after he lived. Diogenes Laertius quotes Hieronymus, a pupil of Aristotle, as saying Thales waited for the moment when our shadows are as long as we are tall, and Pliny says the same. Plutarch tells it with a stick set up at the end of the pyramid’s shadow, so that the pyramid is to the stick as the one shadow is to the other. MacTutor notes that this version comes close to the idea of similar triangles. Nobody knows exactly what Thales did.

Maps and plans. A map at scale 1 : 50,000 is similar to the ground it shows: 1 cm on the map stands for 50,000 cm, or 500 m. Floor plans and blueprints work the same way.

Scale models. Model cars, trains and buildings keep the real shape with every length multiplied by the same factor. Remember that areas and volumes do not scale by that same factor.

Common mistakes

✗Matching sides in the wrong order, like comparing AB with EF.✓Use the naming order: in △ABC ~ △DEF, AB matches DE, BC matches EF and CA matches FD.
✗Setting up a proportion as small/large on one side and large/small on the other.✓Keep the same order in both ratios: small/large = small/large.
✗Multiplying an area by k.✓Areas scale by k² and volumes by k³. Only lengths scale by k.
✗Using the whole side in the side splitter, like AD : AB = AE : EC.✓Compare piece with piece (AD : DB = AE : EC) or part with whole on both sides (AD : AB = AE : AC). Don’t mix them.
✗Calling two sides in proportion and any angle “SAS~.”✓The equal angle must be between the two sides.
✗Thinking similar figures must face the same way.✓Similar figures can be turned or flipped. Match them by angles, not by how they sit on the page.

A short history: Euclid’s Book VI

Euclid’s Elements, written around 300 BCE, treats similar figures in Book VI, built on the theory of ratios from Book V.

  • Proposition 2 is the side-splitter theorem and its converse.
  • Proposition 4: triangles with equal angles have proportional sides (the basis of AA).
  • Proposition 5: triangles with proportional sides have equal angles (SSS~).
  • Proposition 6: one equal angle with the sides around it proportional (SAS~).
  • Proposition 8: the altitude from the right angle makes two triangles similar to the whole and to each other. A corollary says the altitude is a mean proportional between the two pieces of the base.
  • Proposition 19: similar triangles are to one another in the “duplicate ratio” of their matching sides. In modern words, the area ratio is k².

The midsegment theorem as taught today is not one of Euclid’s numbered propositions, though it follows from Proposition 2.

Practice: Scale It

You’ll get four kinds: decide whether two triangles are similar and why, find a missing side, solve a shadow problem, and work with area or volume. Type numbers like 12 or 7.5; fractions like 15/2 work too.

Sources

Credits: all diagrams on this page are original SVG drawings made for Jugami. The pyramid story is retold from the ancient accounts summarized by MacTutor; the shadow figure uses a tree, not a pyramid, so the numbers stay simple.